Question: Problem #1 a) Given 10.4 1= 36 (1/2-pts) CL = 90% r = 112.8 Z= What is Z-value for 90% CL SE = o/V(n) =

Problem #1 a) Given 10.4 1= 36 (1/2-pts) CL = 90%

Problem #1 a) Given 10.4 1= 36 (1/2-pts) CL = 90% r = 112.8 Z= What is Z-value for 90% CL SE = o/V(n) = m = Z*SE = LCL = r - m= UCL = r + m= b) Given 0= 10.4 36 (1/2-pts) CL = 95% r = 112.8 Z = What is Z-value for 95% CL SE = o/V(n) = m = Z*SE - LCL = x - m UCL = x + m= c) Given 0= 10.4 n = 36 (1/2-pts) CL = 99% 112.8 Z = What is Z-value for 99% CL SE = o/V(n) = m = Z*SE = LCL = r - m= UCL - r + m= (1/2-pts) Compare the Margin of Errors for each case, as the Confidence Level increases, what happens to the Margin of Error? Continue down to next page

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