Problem 1. Find the current through the resistance R given in the diagram. Each resistor has a resistance of 4.00 and each battery has a potential of 4.0V. Hint: this can be answered mentally by applying Kirchoff's law to the simplest loop in the circuit. It is up to you to figure out which loop is the 'simplest'.Problem 2. Consider the circuit below- The batteries have voltages of g = :33 = 4-0V and 1 = 2.0V. The resistances are R1 = 1.05] and R; = 2.135]. a} 1What is the current through battery 2 and what is its direction? b) What is the power dissipated through the middle resistor R2? c) What is the power at batter\Problem 3. Consider the circuit diagram below. The battery has a potential of & = 12V and R1 = 20000, R2 = 30000 and R3 = 40000. Find the following potential differences: a) VA - VB, b) VB - VC, c) VC - VD, d) VA - VC. Hint: The symmetry of the problem dictates that the currents through the R, resistors are identical. The same goes for the currents in the R2 resistors.