Problem 18-10 (Algo) Two operators handle adjustments for a group of 10 machines. Adjustment time is exponentially distributed and has a mean of 16 minutes per machine. The machines operate for an average of 84 minutes between adjustments. While running, each machine can turn out 54 pieces per hour. Use Table 1. Table 2 and Table 3. a. Find the probability that a machine will have to wait for an adjustment. (Round your answer to 3 decimal places.) Probability b. Find the average number of machines waiting for adjustment (Round your answer to 2 decimal places.) Average number of machines waiting machines c. Find the average number of machines being serviced (Round your answer to 2 decimal places.) c. Find the average number of machines being serviced. (Round your answer to 2 decimal places.) Average number of machines machines d. The expected hourly output of each machine, taking adjustments into account. (Round your answer to 2 decimal places.) Expected hourly output pieces e. Machine downtime represents a cost of $68 per hour, operator cost (including salary and fringe benefits) is $15 per hour. What is the optimum number of operators? 1 operator 2 operators 3 operators