Question: Problem 2 [1 pt] The following code computes the (integer) square root of a number. If the number is not a perfect square (there is

Problem 2 [1 pt] The following code computes the (integer) square

Problem 2 [1 pt] The following code computes the (integer) square root of a number. If the number is not a perfect square (there is no integer square root), then it returns -1. It does this by trying increasingly large numbers until it finds the right value (or is too high). What is its big O run time? int sqrt(int n ) \{ for (int guess =1; guess* guess

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