Problem $29.(1$ point$)$

$\frac{2x}{x^2-64}-\frac{1}{x+8}=$

$A.\frac{2x-1}{x^2-64}$

$B.x+8$

$C.\frac{1}{x-8}$

$D.\frac{1}{x+8}$

$E.\frac{2x-1}{x^2-x-56}$