Problem $2$: A boiler is filled with $18kg$ water at an initial temperature of $20C.$ Calculate the heat

required $Q$ in $kJ$ for the following stages. Use the liquid water specific heat capacity $c_p=$

$84\mathrm{.}968-0\mathrm{.}0325T\frac{J}{g}$mol.$K,$ where temperature $T$ is in Kelvin. The evaporative heat for water at $1$

atm and $100C,$ is $H=2256k\frac{J}{k}g.$ Use specific heat capacity $c_p=32\mathrm{.}618+0\mathrm{.}001922J\frac{J}{g}$mol.$K$

for steam, where $T$ is in Kelvin.

a$)$ To raise the liquid water temperature from $20C$ to $100C,1$atm $(5$ points$)$

b$)$ To boil all the water in the boilder from $100C$ liquid to $100C$ steam, $1$ atm $(2$ points$)$

c$)$ To raise the $100C$ steam to $200C$ at the same pressure, $1$atm $(3$ points$)$

Problem $2$a:

Your integration of Cp$.$dt needs to be corrected.

The units of Cp are in J$/$gmol K$.$ Your final answer should be in the same units. Accordingly, you must convert $18$kg of water to gmol when calculating heat required, Q$.$

Problem $2$b:

There is no temperature change happening. There is only a phase change. In this case, the heat required will be Q $=$ Evaporite Heat $*$ m$=2256*18$

Problem $2$c:

The units of Cp are in J$/$gmol K$.$ Your final answer should be in the same units. Accordingly, you must convert $18$kg of water to gmol when calculating heat required, Q$.$