Question: Problem 2. Consider Fg = {A ([:]) : AN [s] # 0} from the previous problem. Show that there are at most s sets in

Problem 2. Consider Fg = {A ([:]) : AN [s] # 0} from the previous problem. Show that there are at most s sets in Fg that are pairwise disjoint. That is, show there are s that are pairwise disjoint (for n large enough) and prove there cannot be (s + 1)

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