Question: Problem 2: IP address: 192.168.10.0 / 26 (given) Custom Subnet Mask: 255.255.255.192 Bits Borrowed: _________________________________________ Number of subnets: _________________________________________ Magic number: _________________________________________ Number of valid
Problem 2:
IP address: 192.168.10.0 / 26 (given)
- Custom Subnet Mask: 255.255.255.192
- Bits Borrowed: _________________________________________
- Number of subnets: _________________________________________
- Magic number: _________________________________________
- Number of valid hosts per subnet: 62
- (Sub) network address of subnet 0: 192.168.10.0
- First usable host address in subnet 0: 192.168.10.1
- Last usable host address in subnet 0: 192.168.10.62
- Broadcast address in subnet 0: 192.168.10.63
- (Sub) Network address in subnet 1: _________________________________________
- Last usable host address in subnet 2: _________________________________________
| Subnet | Subnet address | 1st Host address | Last Host address | Broadcast |
| 0 |
|
|
|
|
| 1 |
|
|
|
|
| 2 |
|
|
|
|
| 3 |
|
|
|
|
| Etc. |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Problem 3:
IP address: 192.168.10.0 (given)
Subnet Mask: 255.255.255.240
- Slash prefix: _________________________________________
- Bits Borrowed: _________________________________________
- Number of possible subnets: _________________________________________
- Magic number: _________________________________________
- Number of usable hosts per subnet: _________________________________________
- (Sub) network address of subnet 0: _________________________________________
- First usable host address in subnet 0: _________________________________________
- Last usable host address in subnet 0: _________________________________________
- Broadcast address in subnet 0: _________________________________________
- (Sub) Network address in subnet 1: _________________________________________
- Last usable host address in subnet 2: _________________________________________
| Subnet | Subnet address | 1st Host address | Last Host address | Broadcast |
| 0 |
|
|
|
|
| 1 |
|
|
|
|
| 2 |
|
|
|
|
| 3 |
|
|
|
|
| Etc. |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Problem 4:
IP address: 192.168.10.0 (given)
Minimum number of subnets needed: 31
- Slash prefix: _________________________________________
- Subnet Mask: _________________________________________
- Bits Borrowed: _________________________________________
- Number of possible subnets: _________________________________________
- Magic number: _________________________________________
- Number of valid hosts per subnet: _________________________________________
- (Sub) network address of subnet 0: _________________________________________
- First usable host address in subnet 0: _________________________________________
- Last usable host address in subnet 0: _________________________________________
- Broadcast address in subnet 0: _________________________________________
- (Sub) Network address in subnet 1: _________________________________________
- Last usable host address in subnet 2: _________________________________________
| Subnet | Subnet address | 1st Host address | Last Host address | Broadcast |
| 0 |
|
|
|
|
| 1 |
|
|
|
|
| 2 |
|
|
|
|
| 3 |
|
|
|
|
| Etc. |
|
|
|
|
|
|
|
|
|
|
Problem 5:
IP address: 192.10.10.0 (given) (Note that this address is slightly different than above)
Minimum number of hosts needed per subnet: 16
(Remember that the goal is to find a solution that will waste as few host addresses as possible but still satisfy the requirements.)
- Slash prefix: _________________________________________
- Subnet Mask: _________________________________________
- Bits Borrowed: _________________________________________
- Number of possible subnets: _________________________________________
- Magic number: _________________________________________
- Number of valid hosts per subnet: _________________________________________
- (Sub) network address of subnet 0: _________________________________________
- First usable host address in subnet 0: _________________________________________
- Last usable host address in subnet 0: _________________________________________
- Broadcast address in subnet 0: _________________________________________
- (Sub) Network address in subnet 1: _________________________________________
- Last usable host address in subnet 2: _________________________________________
| Subnet | Subnet address | 1st Host address | Last Host address | Broadcast |
| 0 |
|
|
|
|
| 1 |
|
|
|
|
| 2 |
|
|
|
|
| 3 |
|
|
|
|
| Etc. |
|
|
|
|
|
|
|
|
|
|
Answer the following questions. Try to answer them without using tables to guide you:
- How many usable hosts per sub-network will you have using a /20 address? ______
- Given a Class B address, what is the magic number if you need to subnet using a /23 prefix? ______________________
- In a Class B address, how many sub-networks can you have with a /18 prefix? _______________
- How many total addresses per network can you have with a subnet mask of 255.255.224.0? (Note that total addresses include network and broadcast addresses.)___________
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
