Question: Problem 2: Normal Distribution Answer Questions 7 - 10 (= 2a - 2d) 10 points total Problem 2 Information: The average time (M) required for

 Problem 2: Normal Distribution Answer Questions 7 - 10 (= 2a

- 2d) 10 points total Problem 2 Information: The average time (M)

Problem 2: Normal Distribution Answer Questions 7 - 10 (= 2a - 2d) 10 points total Problem 2 Information: The average time (M) required for Jill to drive to Jackson (City J) is 210 minutes with a standard deviation () of 30 minutes. The average time (M) required to drive to Meridian (City M) is 240 minutes with a standard deviation () of 50 minutes. Use this information to compute the answers for the two questions shown below. Problem 2 a - Normal Distribution for City J: Assuming a normal distribution, the probability that driving to Jackson (City J) will take Jill longer than the average time it normally takes her to drive to Meridian (City M) is (round to 4-places after the decimal). The z-value used for the requested probability computation is (round the z- value to 2-places after the decimal). (Hint: You can view the normal curve diagram for Jackson (City J) in the next question. Formula : Z = (X - H) : 0)

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