Problem $3(10$ pt$).$ The steel ring has a weight W$=0\mathrm{.}5$ N and is suspended on the surface of the water

$($

r

$=1,000$ kg$/$m

$3$

$,$

$=0\mathrm{.}001$ kg$/($m s$)).$

If it takes a force of

P

$=0\mathrm{.}55$ N to lift the ring free from the surface,

determine the surface tension of the water,

s

$.$ Assume a wetting angle of $0$ degrees. The radius of the

ring is R$=50$ mm$,$ and the cross$-$section of the ring is circular with a radius r$=2$ mm$.$