Problem 3 (15 Marks) = = = a) Compare the predictions for the volumetric flow rate at Tw = 1.0 E + 05 Pa for HDPE given in problem 2 at 180C for flow through parallel plates using the power-law (Table 2.6-1 in the textbook). The plate dimensions are: gap (2b) = 2.0 mm; width = 2.00 cm; and length = 5 cm. (10 marks) b) Determine the pressure drop (2 marks) c) Determine the wall shear rate (3 marks). Table 2.6-1. Important expressions for pressure driven flow between two parallel plates n+ 1 Vmax 2n +1 2Q Shear rate at wall Vw w Vw n b b b2 2n + 1 Vavg n [2n +1 2Q Tw = m n 4Wb2 . Tw L/b Shear stress at wall = n Pressure drop [2n +10 Ap = ml 2n W 1" b-(2n+1) 1 2n 1 p Volume rate of flow (per unit width) 1 +2 Q W ba+2 2n +1 ln 22) . 1 n bn+1 Maximum velocity Vo=G240) Vmax n + 1 m n+1 Average velocity Vavg -Vmax 2n +1 Problem 3 (15 Marks) = = = a) Compare the predictions for the volumetric flow rate at Tw = 1.0 E + 05 Pa for HDPE given in problem 2 at 180C for flow through parallel plates using the power-law (Table 2.6-1 in the textbook). The plate dimensions are: gap (2b) = 2.0 mm; width = 2.00 cm; and length = 5 cm. (10 marks) b) Determine the pressure drop (2 marks) c) Determine the wall shear rate (3 marks). Table 2.6-1. Important expressions for pressure driven flow between two parallel plates n+ 1 Vmax 2n +1 2Q Shear rate at wall Vw w Vw n b b b2 2n + 1 Vavg n [2n +1 2Q Tw = m n 4Wb2 . Tw L/b Shear stress at wall = n Pressure drop [2n +10 Ap = ml 2n W 1" b-(2n+1) 1 2n 1 p Volume rate of flow (per unit width) 1 +2 Q W ba+2 2n +1 ln 22) . 1 n bn+1 Maximum velocity Vo=G240) Vmax n + 1 m n+1 Average velocity Vavg -Vmax 2n +1