Question: Problem 3 . ( 2 0 points ) Consider the following MIPS code fragment ( there are many instructions between bne and move ) :

Problem 3.(20 points) Consider the following MIPS code fragment (there are many
instructions between bne and move):
Curr: bne $t1, $t2, Destination
...
...
...
Destination: move $t1, $t2
What is the largest number of instructions that can we have in the program between the
current instruction and the instruction at Destination for the bne instruction to work
correctly? Why ?

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