1 d fsin(10t 1(t) 10 dt at (d) The signal r2(t) is input to the same LTI system with impulse response given below, creating the output ya(t) = 12(t) + h(t) sin h(t) = 2nt n(5t) at A second complex-valued signal is created as below, where the original signal za(t) is the real part and the filter output ya(t) is the NEGATIVE of the imaginary part. 2(t) = ra(t) jua(t) Plot the magnitude of the Fourier Transform Z(w) of the signal 2(t). HINT: 2a(t) = ra(t) ju2(t) = 12(t) + {6(t) jh(t)).