Question: Problem 3 : If there is ever a decision between multiple neighbor nodes in the BFS or DFS algorithms, assume we always choose the letter
Problem : If there is ever a decision between multiple neighbor nodes in the BFS or DFS algorithms, assume we always choose the letter in alphabetical order. a Consider the following adjacency matrix.
A
B
C
D
E
F
G
H
A
B
C
D
E
F
G
H
a Draw the graph that is represented by the matrix.
a In what order will the nodes be visited using Breadth First Search? In what order will the nodes be visited using Depth First Search?
b If you have the adjacency matrix of a graph, and you take the matrix to the Nth power, then the ijth entry of the result tells how many paths of length N there are from vertex i to vertex j here the length is measured in number of edges traversed For example, in a according to the adjacency matrix there is a path of length edge between vertices A and B
A
B
C
D
E
F
G
A
m
C
D
E
F
G
Let G VE be an undirected graph. A triangle in G is a cycle consisting of exactly three vertices or equivalently, three edges Suppose that G is represented as an adjacency matrix. Give an algorithm to determine whether G contains any triangle in Onlog worstcase time.
c Using matrix multiplications, find all the triangles in the graph, represented by the following adjacency matrix.
Step by Step Solution
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock
