Problem $3$

The variables hash$4$ and hash$5$ contain two mystery hashes. I'll give you a hint: they are constructed by taking a word from the rockyou list and appending a single digit. For example, morgan$3$ or shadow$7.$ This is a common thing people to do choose "good" passwords. But they are easy to crack because it's such a predictable pattern.

Write a function to solve this problem for you. Paste your solutions into the word$4$ and word$5$ variables, respectively. You can name the function whatever you want; the function itself won't be checked.

hash$4=\text{'}610$c$23407$eb$63$d$963$c$73$cdda$8703$b$506\text{'}$

hash$5=\text{'}82$f$1742$b$8$fef$8$c$2379698$be$495$c$29$c$3$d$\text{'}$

# You may need this to help solve the problem

digits $=[$b$\text{'}0\text{'},$ b$\text{'}1\text{'},$ b$\text{'}2\text{'},$ b$\text{'}3\text{'},$ b$\text{'}4\text{'},$ b$\text{'}5\text{'},$ b$\text{'}6\text{'},$ b$\text{'}7\text{'},$ b$\text{'}8\text{'},$ b$\text{'}9\text{'}]$

$$

def crack$\_$hash$\_$with$\_$digit$\_$suffix$($target$\_$hash$)$:

digits $=[$b$\text{'}0\text{'},$ b$\text{'}1\text{'},$ b$\text{'}2\text{'},$ b$\text{'}3\text{'},$ b$\text{'}4\text{'},$ b$\text{'}5\text{'},$ b$\text{'}6\text{'},$ b$\text{'}7\text{'},$ b$\text{'}8\text{'},$ b$\text{'}9\text{'}]$

for word in crack$\_$hash$\_$with$\_$digit$\_$suffix:

for digit in digits:

plaintext $=$ word.encode$()+$ digit

hashed $=$ md$5($plaintext$).$hexdigest$()$

if hashed $==$ target$\_$hash:

return plaintext

return None

$$

# Paste your solution here

word$4=$ crack$\_$hash$\_$with$\_$digit$\_$suffix$($hash$4)$

word$5=$ crack$\_$hash$\_$with$\_$digit$\_$suffix$($hash$5)$

$$

$---------------------------------------------------------------------------$

TypeError Traceback $($most recent call last$)$

in

$1$ # Paste your solution here

$---->2$ word$4=$ crack$\_$hash$\_$with$\_$digit$\_$suffix$($hash$4)$

$3$ word$5=$ crack$\_$hash$\_$with$\_$digit$\_$suffix$($hash$5)$

in crack$\_$hash$\_$with$\_$digit$\_$suffix$($target$\_$hash$)$

$4$ def crack$\_$hash$\_$with$\_$digit$\_$suffix$($target$\_$hash$)$:

$5$ digits $=[$b$\text{'}0\text{'},$ b$\text{'}1\text{'},$ b$\text{'}2\text{'},$ b$\text{'}3\text{'},$ b$\text{'}4\text{'},$ b$\text{'}5\text{'},$ b$\text{'}6\text{'},$ b$\text{'}7\text{'},$ b$\text{'}8\text{'},$ b$\text{'}9\text{'}]$

$---->6$ for word in crack$\_$hash$\_$with$\_$digit$\_$suffix:

$7$ for digit in digits:

$8$ plaintext $=$ word.encode$()+$ digit

TypeError: 'function' object is not iterable

# Run this cell to check your answers

from functools import reduce

import operator

assert reduce$($operator$.$mul, word$4)\%0$xffffe $==779296$

assert reduce$($operator$.$mul, word$5)\%0$xffffe $==974694$

$---------------------------------------------------------------------------$

NameError Traceback $($most recent call last$)$

in

$2$ from functools import reduce

$3$ import operator

$---->4$ assert reduce$($operator$.$mul, word$4)\%0$xffffe $==779296$

$5$ assert reduce$($operator$.$mul, word$5)\%0$xffffe $==974694$

NameError: name 'word$4\text{'}$ is not defined

$$