Problem $4\mathrm{.}2(10$ pts$)$: Given that floating$-$point numbers are an approximation anyway, we should devise a way

to round these numbers to two decimal places, as that will be plenty accurate for our purposes. Define and

implement a function named exactly round$\_$to$\_$two, that takes a decimal number and returns that number

rounded to only two decimal places. Your function should round using the $$Half Round$-$Up$$ method, so a number

such as $4\mathrm{.}2568$ would round to $4\mathrm{.}0$ for zero decimal places, $4\mathrm{.}3$ for one, $4\mathrm{.}26$ for two, and so on$.$

To receive any credit for this problem, you are not allowed to use the Python built$-$in round$()$ function!

Hint:

The modulus operator and the floor division operator are handy tools when working with values that are better split into

their remainder and whole divisor portions. While it might be mathematically silly to divide or modulate by one when using

integers, this is a very helpful technique when working with floats!

$123\mathrm{.}456//1\mathrm{.}0$ evaluates to $123\mathrm{.}0$

$123\mathrm{.}456\%1\mathrm{.}0$ evaluates to $0\mathrm{.}456$

In Module $2$ lectures, we presented the technique to round for zero decimal places. If we want to use the same technique

to round to one decimal place, we need to first shift the decimal point one place to the right $($value $*10),$ apply the

technique to round, and shift the decimal point back to the left $($value $=$ value $/10)$ to get the desired result. This

approach can be extended to round to two decimal places!

Examples:

$>>>$ round$\_$to$\_$two$(85\mathrm{.}6397)$

$85\mathrm{.}64$

$>>>$ round$\_$to$\_$two$(98\mathrm{.}75)$

$98\mathrm{.}75$

$>>>$ round$\_$to$\_$two$(8\mathrm{.}1)$

$8\mathrm{.}1$