Question: problem 4 ) find COD and ThOD of 2 . 5 mM of C 4 0 H 8 1 O 2 1 N 8 P

problem 4) find COD and ThOD of 2.5 mM of C40H81O21N8P2?
C40(40)(12.01)=480.4
H81(B1)(1.008)=81.65
O21(21)(16)=336
P2supe(2)(30.97)=61.94
s=(1)(32.07)=32.071104.1491001
ThOD =COD+NOD
NOD
1
(41104.14)sn1 recuics (19132)9 mof O2
(4416.56)gm
(6112)9m
6112(m)4416.56(m)=1,382760,35mg
COD=3820mgl
problem 4 ) find COD and ThOD of 2 . 5 mM of C 4

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