Question: Problem # 5 : Horizontal Curves ( 1 5 points ) A pipeline is defined by a series of tangential lines between points J -

Problem #5: Horizontal Curves (15 points)
A pipeline is defined by a series of tangential lines between points J-K-L-M-N as follows:
\table[[Course,Length (straight line)],[JK,830.00],[KL,965.00],[LM,1210.00],[MN,1750.00]]
The first horizontal curve (connecting lines JK and KL) has a radius of 400.00 feet and an internal angle of 6610'30''. The second horizontal curve (connecting lines KL and LM) has a radius of 600.00 feet and an internal angle of 4342'15''. The third horizontal curve (connecting lines LM and MN) has a radius of 500.00 feet and an internal angel of 5125'48''. Determine the total length of the pipeline between joints J and N incorporating horizontal curves.
A piping configuration in a manufacturing plant is shown in the figure below. Assume that lines AB and CD are Due East. Assume that lines BC and DE are Due North. Using the data provided in the figure, determine the total actual length of the pipe (shown in a solid line) between points A and E. All coordinates (x,y) provided are in feet.
dist A-B=205-55=150
dist B-C=230-135=95
dist C-D=205-100:105'
dist E-D=200-135=65'
Length =150'-30'+47.1'+95'-(30'2)+471'
+105'-(30'2)+47.1+65-30+47.1
Please solve for problem #5. There are two other images that is a similiar problem to #5. Please look at the example problem and solve #5 like the example problem. PLEASE do what is asked. use the steps provided in the example problem to solve for #5 exactly. thank you.
Problem # 5 : Horizontal Curves ( 1 5 points ) A

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