Question: Problem 5 the members are l 1 3 = l 3 4 = 6 m and l 2 3 = 3 m Consider the five

Problem 5 the members are l13=l34=6m and l23=3m
Consider the five member truss shown. The members of the truss have a common cross-sectional area, 9cm62, and are made of the same material with elastic modulus, E=20 GPa. This truss is subjected to the following loading: F2=1kN,P4=P5=500N.P4 and P5 are loaded at x'=l134, and x'=l344 respectively. The lengths of
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I Chapter 2: Development of Plane Truss Equations
a) List the active degrees of freedom of the system
b) write the force to displacement relation for each element in the global coordinate
c) Assemble the global equilibrium equation for the active degrees of freedom, directly
d) Solve the resulting system of equations for the active degrees of freedom
e) Find the strain in each member (element).
Problem 5 the members are l 1 3 = l 3 4 = 6 m and

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