Problem $6$: $(2$ points$)$

A sag VC connects a $-2\mathrm{.}2\%$ grade to a $+2\mathrm{.}4\%$ grade. Elev PVI $=1497\mathrm{.}40ft.$ Elev $LP=1500\mathrm{.}00ft.$ Determine the maximum

safe speed that may be posted along this VC based only on SSD$.($Disregard comfort and appearance for this analysis.$)$

Picture is guide to solve. Unsure how to get L and solve problem

$y_{\text{l}\text{o}\text{w}}^{\text{'}}=\frac{L{G}_1^2}{200(G_1-G_2)}=\frac{(-2,2{)}^{2}L}{200((-2,2)-2,4)}$

$Y_{\text{L}\text{o}\text{v}}^{\text{'}}=$ elevation differeme between $\frac{?}{{?}_P}.$ and PVC$.$

${\displaystyle \underset{\phantom{}}{\overset{\text{E}\text{G}\text{w}\text{P}\text{V}\text{I}}{}}}=2$covpr$+\frac{L{G}_1}{200}=$EtavPVC$+\frac{-2,2L}{200}$

Eher $LP=EtevPVC{Y}_{\text{c}\text{o}\text{w}}^{\text{'}}$

$$ EGrPVC $$ EleVPVI $-\frac{-2,2L}{200}$

Eler $PVC=$ Eler $\frac{?}{{?}_P}-Y_{\text{i}\text{o}\text{n}}^{IN}$

ElevPVI $-\frac{-2,2L}{200}=z_{\text{L}\text{e}\text{v}}LP-y_{\text{c}\text{o}\text{w}}^{\text{'}}$

yow $-\frac{-2,2L}{200}=$zterLP$-$ztorPVI