Problem $6$b$.1$: Show the FBDS

For the beam shown, determine the support reactions at A

and B as well as the internal tractions $($normal force, shear

force and bending moment$)$ at points D and E$.$ Point D is

$($a$)/(2)$ left of the roller at B and point E is $($a$)/(2)$ right of B$.$ The

beam has a self$-$weight of u$=68$l$($b$)/($f$)$t along it's length.

Answers: F$\_($A$)=1167$lb;$,$F$\_($B$)=2373$lb

N$\_($D$)=0$;$,$V$\_($D$)=-885$lb;$,$M$\_($D$)=2819$lb$*$ft

N$\_($E$)=0$;$,$V$\_($E$)=340$lb;$,$M$\_($E$)=-1050$lb$*$ft