Problem $6$:

Repeat problem $5$ with the river replaced by a valley wall. The radius of influence of the well is $920$ m $.$

Hint: The valley represents a no$-$flow boundary. An image well on the opposite side of the valley wall is need. Must use the proper equation The drawdown at points of interest for part $($a$)$ and $($b$)$ needs to be calculated. The distances r$\_\{1\}$ and r$\_\{2\}$ must be calculated from the center of the real and image well to the point of interest, respectively. For part $($a$),$ to find the drawdown at the well, the points of interest can only be at the periphery of the well where ground water flow equation is applicable.