Question: Problem 9 (Force on the Achilles tendon) DG A 75 kg man stands on his toes by exerting an upward force through the Achilles tendon,

 Problem 9 (Force on the Achilles tendon) DG A 75 kg

Problem 9 (Force on the Achilles tendon) DG A 75 kg man stands on his toes by exerting an upward force through the Achilles tendon, as shown below. For the questions FA below, you can assume that one foot supports half the man's 4.01 weight and all torques are measured with respect to the pivot (indicated by a black circle). Use g = 10 m/s2. F, is the tension cmi 12 cm on the Achilles Tendon acting on the heel. The pivot is the point of contact between the foot and the rest of the body, so there Fy is a contact force on the foot at this point which we call Fp- (Note that we ignore the weight of the foot itself.) Pivot FF A. What is the magnitude of the normal force in Newtons? (Hint: one foot supports half the man's weight) B. What is the torque due to the normal force about the pivot? Give you answer in N . m and include a negative sign if needed. C. What force (in N) must the Achilles Tendon exert on the heel to keep the foot in static equilibrium? D. What is the magnitude of the force on the pivot (Fp )? (Hint: the torques and the forces cancel out.)

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