Question: Problem 9.29 - Enhanced - with Solution Part A A uniform bar has two small balls glued to its ends. The bar is 2.70 m

2.70 m long and with mass 3.20 kg , while the balls

each have mass 0.300 kg and can be treated as point masses.

Find the moment of inertia of this combination about an axis perpendicular

to the bar through its center. For related problem-solving tips and strategies,

you may want to Express your answer in kilogram-meters squared. view a

Problem 9.29 - Enhanced - with Solution Part A A uniform bar has two small balls glued to its ends. The bar is 2.70 m long and with mass 3.20 kg , while the balls each have mass 0.300 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis perpendicular to the bar through its center. For related problem-solving tips and strategies, you may want to Express your answer in kilogram-meters squared. view a Video Tutor Solution of An abstract sculpture IVO AED I = kg . m2 Submit Request Answer Part B Find the moment of inertia of this combination about an axis perpendicular to the bar through one of the balls. Express your answer in kilogram-meters squared. IVO AED ? I = kg . m2 Submit Request Answer Part C Find the moment of inertia of this combination about an axis parallel to the bar through both balls. Express your answer in kilogram-meters squared. T = kg . m2 Submit Request AnswerProblem 9.34 Part A A wagon wheel is constructed as shown in the figure below (Figure 1). The radius of the wheel is 0.300 m, and the rim has a mass of 1.50 kg. Each of the wheel's eight spokes, which come out What is the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel? from the center and are 0.300 m long, has a mass of 0.240 kg. Express your answer in kilogram meters squared. for Part A for Part A Vido for Party redo for Part A reset for Part A keyboard shortcuts for Part A keyboard shortcuts kg . m Submit Previous Answers Request AnswerA solid uniform 3.25-kg cylinder, 70.0 cm in diameter and 12.4 cm long, is connected to a 1.50-kg weight over two massless frictionless pulleys as shown in the figure below (gw). The cylinder is free to rotate about an axle through its center perpendicular to its circular faces. and the system is released from rest. Figure 1 0H V PartA How far must the 1.50-kg weight fall before it reaches a speed of 3.50 m/s? Express your answer in meters. Muest Answer 3.25 kg 1.50 kg Part A How far must the 1.50-kg weight fall before it reaches a speed of 3.50 m /s? Express your answer in meters. VO AEQ ? d = m Submit Request Answer Part B How fast is the cylinder turning at this instant? Express your answer in radians per second. VO AEQ ? W = rad/s Submit Request AnswerA string is wrapped several times around the rim of a small hoop with a radius of 0.0800 In and a mass of 0.170 kg. The free end of the string is held in place and the hoop is released from rest (see (gure 1)). Figure 1 of1 0.0800 m V PartA Calculate the angular speed of the rotating hoop after it has descended 0.750 1121. Express your answer in radians per second. Submit Previous Answers Ft_equest

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