Question: Problem A: You have been given the 1 9 2 . 1 6 8 . 2 0 . 0 / 2 4 network address to

Problem A:
You have been given the 192.168.20.0/24 network address to subnet, with the following topology.
Step 1: Determine the number of subnets in Network Topology A.
Question 1
2
Points
How many subnets are there?
Remember:
All LANs connected to Routers are to be counted as a subnet
Router1(R1) to Router2(R2) is to be counted as a subnet.
Router2(R2) to Router3(R3) is to be counted as a subnet.
Router1(R1)to Router3(R3) is to be counted as a subnet.
Add your answer
Integer, decimal, or E notation allowed
Question 2
2
Points
How many bits should you borrow to create the required number of subnets?
Add your answer
Integer, decimal, or E notation allowed
Question 3
3
Points
How many usable host addresses per subnet are in this addressing scheme?
Note: Usable host addresses =2(h)-2 where h is the number of host bits left in the new subnet mask
Add your answer
Integer, decimal, or E notation allowed
Question 4
2
Points
What is the new subnet mask in dotted decimal format?
Note: Type full subnet mask
Blank 1
Blank 1
Add your answer
Dotted decimal
Binary
Original subnet mask =255.255.255.0
11111111111111111111111100000000
New subnet mask =???.???.???.???
Question 5
2
Points
What is the new CIDR notation for each new subnet? (original network =/24)
Note: Just type number
Add your answer
Integer, decimal, or E notation allowed
Question 6
3
Points
What is the increment between subnets?
Add your answer
Integer, decimal, or E notation allowed
Question 7
2
Points
How many subnets are available for future use?
Add your answer
Integer, decimal, or E notation allowed
Step 2: Record the subnet information.
Note: This is a template format you can sketch to practice and duplicate (in the answers below). Not all rows will be used in this assignment
Subnet Number
Subnet Address
First Usable Host Address
Last Usable Host Address
Broadcast Address
0(1st)
1(2nd)
2(3rd)
3(4th)
4(5th)
5(6th)
6(7th)
7(8th)
Question 8
6
Points
1st subnet > also called Subnet 0
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 9
6
Points
2nd subnet > also called Subnet 1
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 10
6
Points
3rd subnet > also called Subnet 2
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 11
6
Points
4th subnet > also called Subnet 3
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 12
6
Points
5th subnet > also called Subnet 4
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 13
6
Points
6th subnet > also called Subnet 5
Subnet Address
Blank 1
First Usable (Valid) Host Address
Blank 2
Last Usable (Valid) Host Address
Blank 3
Broadcast Address
Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
Question 14
5
Points
Future Use:
Identify the Subnet Addresses for each of the future user subnets
7th Subnet Address
Blank 1
8th Subnet Address
Blank 2
Blank 1
Add your answer
Blank 2
Add your answer
Re-Review your borrowed bits and subnetting tables (if needed) to answer the question above.
 Problem A: You have been given the 192.168.20.0/24 network address to

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