Question: Problem Description: Credit card numbers follow certain patterns. A credit card number must have between 13 and 16 digits. It must start with: 4 for
Problem Description:
Credit card numbers follow certain patterns. A credit card number must have between 13 and 16 digits. It must start with:
4 for Visa cards
5 for Master cards
37 for American Express cards
6 for Discover cards
In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine if a card number is entered correctly or if a credit card is scanned correctly by a scanner. Almost all credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustration, consider the card number 4388576018402626):
1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number.
2 * 2 = 4
2 * 2 = 4
4 * 2 = 8
1 * 2 = 2
6 * 2 = 12 (1 + 2 = 3)
5 * 2 = 10 (1 + 0 = 1)
8 * 2 = 16 (1 + 6 = 7)
4 * 2 = 8
2. Now add all single-digit numbers from Step 1.
4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37
3. Add all digits in the odd places from right to left in the card number.
6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38
4. Sum the results from Step 2 and Step 3.
37 + 38 = 75
5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid.
Write a program that prompts the user to enter a credit card number as a long integer. Display whether the number is valid or invalid.
Here are sample runs of the program:
Sample 1:
Enter a credit card number as a long integer: 4246345689049834
4246345689049834 is invalid
Sample 2:
Enter a credit card number as a long integer: 4388576018410707
4388576018410707 is valid
CODE SKELETON
import java.util.Scanner;
public class Lab12 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a credit card number as a long integer: ");
long number = input.nextLong();
if (isValid(number))
System.out.println(number + " is valid");
else
System.out.println(number + " is invalid");
}
/** Return true if the card number is valid */
public static boolean isValid(long number) {
return (getSize(number) >= 13) && (getSize(number) <= 16) &&
(prefixMatched(number, 4) || prefixMatched(number, 5) ||
prefixMatched(number, 6) || prefixMatched(number, 37)) &&
(sumOfDoubleEvenPlace(number) + sumOfOddPlace(number)) % 10 == 0;
}
/** Get the result from Step 2 */
public static int sumOfDoubleEvenPlace(long number) {
int result = 0;
// Implementation left as exercise
return result;
}
/** Return this number if it is a single digit, otherwise, return
* the sum of the two digits */
public static int getDigit(int number) {
int result=0;
// Implementation left as exercise
Return result;
}
/** Return sum of odd place digits in number */
public static int sumOfOddPlace(long number) {
int result = 0;
// Implementation left as exercise
return result;
}
/** Return true if the digit d is a prefix for number */
public static boolean prefixMatched(long number, int d) {
return getPrefix(number, getSize(d)) == d;
}
/** Return the number of digits in d */
public static int getSize(long d) {
int numberOfDigits = 0;
// Implementation left as exercise
return numberOfDigits;
}
/** Return the first k number of digits from number. If the number
* of digits in number is less than k, return number. */
public static long getPrefix(long number, int k) {
long result = number;
// Implementation left as exercise
return result;
}
}
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
