Problem H$)$

In the Figure shown below, if pressure at $B,P_8=140$kPa find pressure at $A,P_A.$

Given: Specific Gravity of Oil, $S{G}_{\text{o}\text{i}\text{l}}=0\mathrm{.}86,$ Specific Gravity of Mercury, $S{G}_{\text{m}\text{e}\text{r}\text{c}\text{a}\text{r}\text{y}}=13\mathrm{.}6,$ Specific Gravity of Kerosene, $S{G}_{kerosene}=0\mathrm{.}82,$

Specific Weight of Water, ${}_{\text{w}\text{a}\text{t}\text{e}\text{r}}=9790\frac{N}{m^3},$ Specific Weight of Air, ${}_{\text{a}\text{i}\text{r}}=12\frac{N}{m^3}.$ Also, $h_1=24\mathrm{.}0cm,h_2=18\mathrm{.}0cm,h_3=12\mathrm{.}0cm,h_4=10\mathrm{.}0cm,h_5=5\mathrm{.}0cm.$

Show all calculations. Solve in SI Units.Problem H$)$

In the Figure shown below, if pressure at $B,P_8=140$kPa find pressure at $A,P_A.$

Given: Specific Gravity of Oil, $S{G}_{\text{o}\text{i}\text{l}}=0\mathrm{.}86,$ Specific Gravity of Mercury, $S{G}_{\text{m}\text{e}\text{r}\text{c}\text{a}\text{r}\text{y}}=13\mathrm{.}6,$ Specific Gravity of Kerosene, $S{G}_{kerosene}=0\mathrm{.}82,$

Specific Weight of Water, ${}_{\text{w}\text{a}\text{t}\text{e}\text{r}}=9790\frac{N}{m^3},$ Specific Weight of Air, ${}_{\text{a}\text{i}\text{r}}=12\frac{N}{m^3}.$ Also, $h_1=24\mathrm{.}0cm,h_2=18\mathrm{.}0cm,h_3=12\mathrm{.}0cm,h_4=10\mathrm{.}0cm,h_5=5\mathrm{.}0cm.$

Show all calculations. Solve in SI Units.