Problem III. ( 24 points) CIRCLE (A, B, C, D, or E) corresponding to the BEST answer. Only ON LETTER should be CIRCLED for each of the six questions. (1) ] Both the Scheffe procedure and the Tukey HSD procedure have exact experimentwise error rates. WI is the number of pairs of treatments declared to be significantly different by the Tukey HSD procedu generally greater than the number of pairs declared by the Scheffe procedure? A. HSD has a higher Type I error rate than the Type I error rate for Scheffe. B. Scheffe considers all contrasts not just the contrasts dealing with pairwise differences; whereas, HS is just considering pairwise differences. C. Scheffe fails to take into account all the factors; whereas HSD does. D. HSD uses an estimate of the standard error which tends to be smaller than the value used by Scheft E. None of the above are correct