Question: Problem Statement: A toy car weighing 0 . 7 2 lb has been released at the top of the track. The curved portion of the

Problem Statement:
A toy car weighing 0.72 lb has been released at the top of the track. The curved portion of the track is described by the equation
r()=8(1-cos()) ft. When the car reaches a position of =252, its speed is 30.3fts, and the radius of curvature of the track
is 8.62951 ft . Neglecting the car's size and friction, determine the following for the instant in question.
Tip: The track is drawn to scale. Consider printing the figure, drawing the car at your value of , then drawing the unit vectors
accordingly. You can enlarge the figure by clicking on it. The answers depend on proper definition of the unit vectors.
The angle =
The angle =
(i.e. the angle between gravity and tangent; it will be obtuse if the car has already passed the
bottom of the track.)
The normal component of acceleration:
The tangential component of acceleration:
The net normal force on all wheels at the instant in question.
Finally, resolve the acceleration into cylindrical components:
The radial acceleration component, ar=
The transverse acceleration component, a=
Problem Statement: A toy car weighing 0 . 7 2 lb

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!