Question: PROBLEMS 2 9 . 1 . Trap rock is crushed in a gyratory crusher. The feed is nearly uniform 2 - in . spheres. The

PROBLEMS
29.1. Trap rock is crushed in a gyratory crusher. The feed is nearly uniform 2-in. spheres. The differential screen analysis of the product is given in column (1) of Table 29.5. The power required to crush this material is 400kW? ton. Of this 10kW is needed to operate the empty mill. By reducing the clearance between the crushing head and the cone, the differential screen analysis of the product becomes that given in column (2) in Table 29.5. From (a) Rittinger's law and (b) Kick's law, calculate the power required for the second operation. The feed rate is 110 ton/h.
TABLE 29.5
Data for Prob. 29.1
\table[[,Product],[Mesh,\table[[First grind],[(1)]],\table[[Second grind],[(2)]]],[46,3.1,],[68,10.3,3.3],[810,20.0,8.2],[1014,18.6,11.2],[1420,15.2,12.3],[2028,12.0,13.0],[2835,9.5,19.5],[3548,6.5,13.5],[4865,4.3,8.5],[-65,0.5,],[65100,,6.2],[100150,,4.0],[-150,,0.3]]
 PROBLEMS 29.1. Trap rock is crushed in a gyratory crusher. The

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