Problems #$2$ and #$3$ are based on the following information:

A back tangent with a $7\%$ grade meets a forward tangent with a $-5\%$ grade on a vertical alignment. A $350$

feet horizontal length of a vertical curve is placed such that the point of vertical curvature $($PVC$)$ is at

station $10+35$ at an elevation of $60\mathrm{.}0$ feet.

Problem #$2$

The vertical curve elevation at station $11+35$ is most nearly:

A$.65$ feet

B$.67$ feet

C$.69$ feet

D$.71$ feet

Problem #$3$

The tangent elevation at the point of vertical intersection $($PVI$)$ is most nearly:

A$.66$ feet

B$.68$ feet

C$.70$ feet

D$.72$ feet