Question: Procedure For the differential equation y - y' - 6y= 0, the substitutions y = Y and y2y' lead to the system y =

Procedure For the differential equation y" - y' - 6y= 0, the

Procedure For the differential equation y" - y' - 6y= 0, the substitutions y = Y and y2y' lead to the system y = Y2 = y2 = 6y1 + y2 Use the procedure to solve y" + y' 42y = 0. NOTE: Use c and c for the constants of integration. Y1 =

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