program in C$++$ with inline assembly $($needs to be $.$cpp source code with embedded assembly$)$

The problem:

please use my bit map creation program as reference:

#include

#include

#include

using namespace std;

#define IMAGE$\_$SIZE $256$

void drawLine$($int x$0,$ int y$0,$ int x$1,$ int y$1,$ char bits$[$IMAGE$\_$SIZE$][$IMAGE$\_$SIZE$])$;

int main$()\{$

$//$ Initializes the bitmap array

char bits$[$IMAGE$\_$SIZE$][$IMAGE$\_$SIZE$]$;

for $($int i $=0$; i $<$ IMAGE$\_$SIZE; $++$i$)\{$

for $($int j $=0$; j $<$ IMAGE$\_$SIZE; $++$j$)\{$

bits$[$i$][$j$]=255-$ static$\_$cast$((255\mathrm{.}0/$ IMAGE$\_$SIZE$)*$ i$)$;

$\}$

$\}$

$//$ User input

cout $<<$ "Enter two pairs of point coordinates in the range of $0-"<<$ IMAGE$\_$SIZE $-1<<"$:$"<<$ endl;

int x$0,$ y$0,$ x$1,$ y$1$;

cin $>>$ x$0>>$ y$0>>$ x$1>>$ y$1$;

$//$ Checks if input values are within range

if $($x$0<0||$ x$0>=$ IMAGE$\_$SIZE $||$ y$0<0||$ y$0>=$ IMAGE$\_$SIZE $||$

x$1<0||$ x$1>=$ IMAGE$\_$SIZE $||$ y$1<0||$ y$1>=$ IMAGE$\_$SIZE$)\{$

cout $<<$ "Value out of range, ending." $<<$ endl;

return $-1$;

$\}$

drawLine$($x$0,$ y$0,$ x$1,$ y$1,$ bits$)$;

ofstream bmpOut$("$output$.$bmp$",$ ios::out $|$ ios::binary$)$;

if $(!$bmpOut$)\{$

cout $<<$ "Could not open file, ending." $<<$ endl;

return $-1$;

$\}$

BITMAPFILEHEADER bmfh;

BITMAPINFOHEADER bmih;

RGBQUAD colors$[256]$;

bmfh$.$bfType $=0$x$4$d$42$;

bmfh$.$bfReserved$1=0$;

bmfh$.$bfReserved$2=0$;

bmfh$.$bfOffBits $=$ sizeof$($bmfh$)+$ sizeof$($bmih$)+$ sizeof$($colors$)$;

bmfh$.$bfSize $=$ bmfh$.$bfOffBits $+$ IMAGE$\_$SIZE $*$ IMAGE$\_$SIZE; $//$ Actual size of the bitmap data

bmih.biSize $=$ sizeof$($BITMAPINFOHEADER$)$;

bmih.biWidth $=$ IMAGE$\_$SIZE;

bmih.biHeight $=$ IMAGE$\_$SIZE;

bmih.biPlanes $=1$;

bmih.biBitCount $=8$; $//8-$bit grayscale

bmih.biCompression $=$ BI$\_$RGB;

bmih.biSizeImage $=0$;

bmih.biXPelsPerMeter $=2835$; $//$ Standard resolution

bmih.biYPelsPerMeter $=2835$;

bmih.biClrUsed $=0$; $//0$ colors used

bmih.biClrImportant $=0$;

$//$Sets Bitmap with a grayscale background

for $($int i $=0$; i $<256$; $++$i$)\{$

colors$[$i$].$rgbBlue $=$ colors$[$i$].$rgbGreen $=$ colors$[$i$].$rgbRed $=$ i;

colors$[$i$].$rgbReserved $=0$;

$\}$

$//$ Write headers to the file

bmpOut.write$($reinterpret$\_$cast$($&bmfh$),$ sizeof$($bmfh$))$;

bmpOut.write$($reinterpret$\_$cast$($&bmih$),$ sizeof$($bmih$))$;

bmpOut.write$($reinterpret$\_$cast$($colors$),$ sizeof$($colors$))$;

$//$ Write bitmap data

bmpOut.write$($reinterpret$\_$cast$($bits$),$ IMAGE$\_$SIZE $*$ IMAGE$\_$SIZE$)$;

bmpOut.close$()$;

$//$ Opens bitmap in Windows Paint

system$("$mspaint output.bmp$")$;

return $0$;

$\}$

$//$ Draws line

void drawLine$($int x$0,$ int y$0,$ int x$1,$ int y$1,$ char bits$[$IMAGE$\_$SIZE$][$IMAGE$\_$SIZE$])\{$

int dx $=$ abs$($x$1-$ x$0)$;

int dy $=$ abs$($y$1-$ y$0)$;

int sx $=$ x$0<$ x$1?1$ : $-1$;

int sy $=$ y$0<$ y$1?1$ : $-1$;

int err $=$ dx $-$ dy;

while $($true$)\{$

$//$ Calculate brightness based on distance from the start point

float brightness $=255\mathrm{.}0$f $*(($float$)($dx $-$ abs$($x$0-$ x$1))/$ dx$)$;

bits$[$y$0][$x$0]=$ static$\_$cast$($brightness$)$; $//$ Set pixel to grayscale value

$//$ Increase line width by $2$ pixels

for $($int i $=1$; i $<=2$; $++$i$)\{$

if $($y$0+$ i $<$ IMAGE$\_$SIZE$)\{$

bits$[$y$0+$ i$][$x$0]=$ static$\_$cast$($brightness$)$;

$\}$

if $($y$0-$ i $>=0)\{$

bits$[$y$0-$ i$][$x$0]=$ static$\_$cast$($brightness$)$;

$\}$

$\}$

if $($x$0==$ x$1$ && y$0==$ y$1)$ break;

int e$2=2*$ err;

if $($e$2>-$dy$)\{$ err $-=$ dy; x$0+=$ sx; $\}$

if $($e$2<$ dx$)\{$ err $+=$ dx; y$0+=$ sy; $\}$

$\}$

$\}$

$---------$

use this program to to draw lines in a bit map which provide a geographic map outline. Please adjust code so that the line calculating part is in inline assembly

$--------$

After creating the basic bit map $(1024$ by $1024$ pixels$),$ your program will read a text file which contains pairs of longitude and latitude numbers $($in that order$).$ These values will be positive, and will be within the following dimensions:

North $-$ maximum latitude $=38\mathrm{.}995110$

West $-$ maximum longitude $=-77\mathrm{.}119900$

South $-$ minimum latitude $=38\mathrm{.}791513$

East $-$ minimum longitude $=-76\mathrm{.}909395$

$($For longitude, maximum and minimum are relative to their absolute value.$)$

$----$ here is the text file: DCBoundaryFile.txt

District of Columbia

$-77\mathrm{.}03859838\mathrm{.}791513$

$-77\mathrm{.}03889838\mathrm{.}800813$

$-77\mathrm{.}03579838\mathrm{.}814913$

$-77\mathrm{.}03809838\mathrm{.}815613$

$-77\mathrm{.}03909838\mathrm{.}821413$

$-77\mathrm{.}03809838\mathrm{.}828612$

$-77\mathrm{.}03919938\mathrm{.}832212$

$-77\mathrm{.}04119938\mathrm{.}833712$

$-77\mathrm{.}04259938\mathrm{.}833812$

$-77\mathrm{.}04349938\mathrm{.}833212$

$-77\mathrm{.}04489938\mathrm{.}834712$

$-77\mathrm{.}04499938\mathrm{.}838512$

$-77\mathrm{.}04419938\mathrm{.}840212$

$-77\mathrm{.}04169938\mathrm{.}840212$

$-77\mathrm{.}03279838\mathrm{.}841712$

$-77\mathrm{.}03169838\mathrm{.}850512$

$-77\mathrm{.}03929938\mathrm{.}864312$