// Program to determine tomorrow's date

#include

#include

struct date

{ int month; int day; int year; };

// Function to calculate tomorrow's date

struct date dateUpdate (struct date today)

{struct date tomorrow;

int numberOfDays (struct date d);

if ( today.day != numberOfDays (today) ) {

tomorrow.day = today.day + 1;

tomorrow.month = today.month;

tomorrow.year = today.year;

} else if ( today.month == 12 ) { // end of year

tomorrow.day = 1;

tomorrow.month = 1;

tomorrow.year = today.year + 1;

}

else { // end of month

tomorrow.day = 1;

tomorrow.month = today.month + 1;

tomorrow.year = today.year;

}

return tomorrow;

}

// Function to find the number of days in a month

int numberOfDays (struct date d)

{

int days;

bool isLeapYear (struct date d);

const int daysPerMonth[12] =

{ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

if ( isLeapYear (d) && d.month == 2 )

days = 29;

else

days = daysPerMonth[d.month - 1];

return days;

}

// Function to determine if it's a leap year

bool isLeapYear (struct date d)

{

bool leapYearFlag;

if ( (d.year % 4 == 0 && d.year % 100 != 0) ||

d.year % 400 == 0 )

leapYearFlag = true; // It's a leap year

else

leapYearFlag = false; // Not a leap year

return leapYearFlag;

}

int main (void)

{

struct date dateUpdate (struct date today);

struct date thisDay, nextDay;

printf ("Enter today's date (mm dd yyyy): ");

scanf ("%i%i%i", &thisDay.month, &thisDay.day, &thisDay.year);

nextDay = dateUpdate (thisDay);

printf ("Tomorrow's date is %i/%i/%.2i. ",nextDay.month,

nextDay.day, nextDay.year % 100);

return 0;

}

Looking for someone to replace the dateUpdate() function with compound literals. Also looking for the int main (void) to be moved from the bottom of the code to the top. All I need changed is the dateUpdate() function and the int main (void) to be moved under the #include and #include . Thanks in advance.