Project $2$: A Program Simulating Modified MARIE$$s Computer

Language: Python

Input:

A text file containing decimal $($not Hex$)$ machine code $($not assembly code$)$ for MARIE$$s computer following instruction set described in chapter $4.$ Instructions are in different lines $($no need for semicolon at the end of each instruction$)$

Output:

Any output specified in the input file by $6000$ will be displayed on screen

Computer specification:

Generally the same as in chapter $4$:

$1000$ memory address: $000999$

$$ Four digits decimal instruction or data in each memory slot.

$$ One PC$,$ one AC$,$ one IR$,$ one MBR$,$ one MAR

$$ The program in the input file needs to be loaded into memory first and stored in consecutive slots starting from address $000$

$$ Instruction $5000$ will ask user$$s input from keyboard, $6000$ displays content in calculator

$$ Instruction $8000$ will skip next instruction if AC$<0.$ Instruction $8100$ will skip next instruction if AC$=0.$ Instruction $8200$ will skip next instruction if AC$>0$

Other requirements:

Your program should accept any length of input program that can be fit in MARIE$$s $1000$ memory slots and generate correct result and$/$or output on screen.

Submit the source code together with readme file with instruction to compile, build and use your program

Example:

Input file contains following code $($return positive difference$)$:

$5000$

$2011$

$5000$

$2012$

$4011$

$8000$

$9009$

$1011$

$4012$

$6000$

$7000$

Running of the program with this input will ask user to input $2$ numbers, let's say $5$ and $10,$ the program will output the positive difference on the screen, which is $5.$

Address Content Comment

$0005000$ Input the first number

$0012011$ Save the first number to address $011$

$0025000$ Input the second number

$0032012$ Save the second number to address $012$

$0044011$ Second number $$ First number, result in AC

$0058000$ If AC$<0$ jump to address $007$

$0069009$ Jump to address $009$

$0071011$ Load the first number to AC

$0084012$ First number $$ second number, result in AC

$0096000$ Print AC$$s value

$0107000$ Halt

$011$ Storage for first number

$012$ Storage for second number