Project Name:

$\_$ADC$\_$Compare$\_$ANO

Description:$-$ This program reads the Analog voltage from the potentiometer on input $"$AN$0($RA$0)"$ and turns ON the LED connected to pin $"$RB$0"$ if the input voltage is greater than approximately $2\mathrm{.}5$ V $.$ The LED is turned OFF if the input voltage is less than approximately $2\mathrm{.}5$ V $.$

Tip: In Proteus, use Page Up$/$Page Down keys to adjust the Pot value while hovering over it

Instructions:$-$

$1.$ Create a macro name for the LED:$-$

E$.$g$.\backslash$#define LED RB$0$

$2.$ Create a macro name for ON and OFF :$-$

E$.$g$.\backslash$#define ON $1$

$\backslash$#define OFF $0$

$3.$ Use the macros listed above in your program.

$4.$ Setup RB$0$ pin as a Digital Output.

$5.$ Setup AN$0/$RA$0$ pin as an Analog input.

$6.$ Setup the ADC as follows $($see ADCON$0\backslash$& ADCON$1$ registers on pages $114/115$ of the PIC$16$F$188$ Datasheet$)$:$-$

ADCON$0$

$-$ Setup "ADCS $\backslash (<mn>1</mn>$: $0>\backslash )"$ bits to select the internal RC oscillator

$-$ Setup $"$CHS$<mn>2</mn>$:$0>"$ to select Channel $0($i$.$e$.$ RA$0/$AN$0)$

Note:$-$ you can write directly to ADCONO or you can also write directly to the Channel Select Bits defined in header file:ADCONObits.CHS $=$ xx;

$-$ Setup "ADON" bit to turn on A$/$D module

ADCON$1$

$-$ Setup "ADFM" bit to select Left Justified result

$-$ Setup "ADCS$2"$ bit as disabled

$-$ Setup $"$VCFG $\backslash (<mn>1</mn>$: $0>\backslash )"$ bits to use AVDD and AVss

$7.$ Create an $8-$bit variable called "adc$\_$val" to store the value of the ADC result.

$8.$ Inside a continuous loop, start an AD C conversion by writing to the $"$GO$\_$DONE" bit.

$9.$ Wait until the ADC conversion has completed.

$10.$ Turn ON the LED connected to pin RBO if the digitised input voltage adc$\_$val is greater than or equal to $2\mathrm{.}5$ V otherwise turn OFF the LED.

$11.$ Add comments to your code $($marks lost for no comments$).$

$12.$ Ensure all code is properly indented $($i$.$e$.$ marks lost for no indentation$).$

Inputs:$-1($i$.$e$.$ AN$0($RA$0))$

Outputs:$-1($i$.$e RB$0)$