Property line AA$\text{'}$ is intersecting the alignment shown below at point P$.$

The azimuth of the back tangent is $0\backslash$deg $0\text{'}0",$ the angle of intersection is $36\backslash$deg $4200,$ the radius of the

curve is $500\mathrm{.}00$ ft$,$ and PC is at station $38+55\mathrm{.}00.$

The line AA$\text{'}$ is crossing the back tangent at point Q$,145\mathrm{.}00$ ft from PC$.$

a$.(5$ pts$)$ Using as origin the center of the circular arc, find the coordinates of the of point P