Proportion Question:

11. An Air Quality instrument logs when standards are not met and 1 when

standards are met. The log is saved to file DATA First, compute the proportion meeting standard as the mean of

Air Quality values. Second, at alpha = 0.10 (sensitive, exploratory), test the hypothesis thatproportion of times that air quality meets standards is at least 90%

Data

Time 0:00:00 0:00:30 0:01:00 0:01:30 0:02:00 0:02:30 0:03:00 0:03:30 0:04:00 0:04:30 0:05:00 0:05:30 0:06:00 0:06:30 0:07:00 0:07:30 0:08:00 0:08:30 0:09:00 0:09:30 0:10:00 0:10:30 0:11:00 0:11:30 0:12:00 0:12:30 0:13:00 0:13:30 0:14:00 0:14:30 0:15:00 0:15:30 0:16:00 0:16:30 0:17:00 0:17:30 0:18:00 0:18:30 0:19:00 0:19:30 0:20:00 0:20:30 0:21:00 0:21:30 0:22:00 0:22:30 0:23:00 0:23:30

Air Quality 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1

a) The pvalue of 0.062 indicates that the data provide strong evidence against HO: 0.90

HO is rejected at = 0.10.The status quo has changed

b) The pvalue of 0.006 indicates that the data provide overwhelming evidence against HO:

0.90.HO is rejected at = 0.10.Send out an air quality alert.

c)The pvalue of 0.966 indicates that the data provide insignificant evidence against HO: (Is this the correct answer?)

0.90. HO is not rejected at =0.10. The status quo remains unchanged. None of the answers are correct.

d) The pvalue of 0.062 indicates that the data provide weak evidence against HO: 0.90

HO is rejected at = 0.10.

e) None of the answers are correct

Thank you!