Question: Prove that for all n (n E N, n 2), it is possible to divide numbers 1, 2, 3, ...3n into 3 groups so

Prove that for all n (n € N, n > 2), it is possible to divide numbers 1,2,3,...3n into 3 groups so that each group has n numb 

Prove that for all n (n E N, n 2), it is possible to divide numbers 1, 2, 3, ...3n into 3 groups so that each group has n numbers and the sums of n numbers in all groups are the same.

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Solu tion Proof We always make group of 6 numbers Such that the three groups of two numbers ... View full answer

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