Prove that for positive integers a, m>1, the following congruence holds : a^{m} = a^{m-phi(m)} (mod m)

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Prove that for positive integers a, m>1, the following congruence holds :

a^{m} = a^{m-phi(m)} (mod m)

Related Book For answer-question

Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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Posted Date: Nov 30, 2019 12:01 AM

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Prove that for positive integers a, m>1, the following congruence holds : a^{m} = a^{m-phi(m)} (mod m)

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Calculus Early Transcendentals

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