Question: Prove that the function fdefined on [0, 1] as f (x) = 2n, if x = - where n = 1, 2, ... n =
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Prove that the function fdefined on [0, 1] as f (x) = 2n, if x = - where n = 1, 2, ... n = 0, otherwise is not Riemann-integrable on [0, 1]. (Hint: lim f (x) = co, f is not bounded above and so not Riemann integrable on [0, 1]) X-0
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