Prove the trigonometric identity.

$\frac{secxsinx}{tanx+cotx}=si{n}^{2}x$

Drag $an$ expression $to$ each box $to$ correctly complete the proof.

$\frac{secxsinx}{tanx+cotx}=si{n}^{2}x$

$=si{n}^{2}x$

$=si{n}^{2}x$

$=si{n}^{2}x$

$=si{n}^{2}x$

$=si{n}^{2}x$

$si{n}^{2}x=si{n}^{2}x$

$\frac{\frac{sinx}{cosx}}{\frac{1}{sinxcosx}}\frac{\frac{cosx}{sinx}}{\frac{si{n}^{2}x+co{s}^{2}x}{sinxcosx}}$

$\frac{\frac{sinx}{cosx}}{\frac{si{n}^{2}x+co{s}^{2}x}{sinxcosx}}$

$\frac{\frac{1}{cosx}*sinx}{\frac{sinx}{cosx}+\frac{cosx}{sinx}}$

$\frac{\frac{sinx}{cosx}}{\frac{si{n}^{2}x}{sinxcosx}+\frac{co{s}^{2}x}{sinxcosx}}$

$\frac{sinx}{cosx}*sinxcosx$

$\frac{\frac{cosx}{sinx}}{\frac{si{n}^{2}x}{sinxcosx}+\frac{co{s}^{2}x}{sinxcosx}}$