Question: Prove whether or not S is a CFL. S={w {a,b,c}*|#a(w) = #b(w) and #b(w) #c(w)(mod3)} #b(w) #c(w)(mod3) means that #b(w) mod 3 =#c(w) mod 3

Prove whether or not S is a CFL.

S={w Prove whether or not S is a CFL. S={w{a,b,c}*|#a(w) = #b(w) and {a,b,c}*|#a(w) = #b(w) and #b(w) #b(w) #c(w)(mod3)} #b(w) #c(w)(mod3) means that #b(w) mod 3 =#c(w) mod 3 #c(w)(mod3)}

#b(w) If it is CFL, please draw a PDA for it. #c(w)(mod3) means that #b(w) mod 3 =#c(w) mod 3

If it is CFL, please draw a PDA for it.

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