PROVIDE ME A DETAILED SOLUTION AND COMPLETE SOLUTION AND DON'T COPY FROM CHATGPT IT IS OF NO USE.

a$.$ Consider the following Verilog module.

module top$($in$1,$ in$2,$ clk$,$ out$)$;

input in$1,$ in$2,$ clk; output out;

reg q$1,$ q$2$;

always @ $($posedge clk$)$ qin$1$ & in$2)$;

always @ $($posedge clk$)$ qin$1$ & in$2)$;

always @$*$ out $=!($q$1$ & q$2)$;

endmodule

Draw the schematic of the synthesized netlist and mark the circuit elements. Assume that

the library used in synthesis contains only the following circuit elements: inverter, two$-$

input NAND gate, and D flip$-$flop.

b$.$ Consider the unoptimized netlist $($circuit$)$ generated

by an RTL synthesis tool shown alongside. The

numbers on the nets indicate the number of lines in

a bus. The multiplexer selects one of the four buses

based on the select lines s$0$ and s$1.$ The elements

marked $*$ are multipliers.

Redraw the circuit with resource sharing that

minimizes the circuit area $($mark the number of lines

in each bus$).$ Assume that the area of a multiplier is

significantly higher than the multiplexers. Hence, the

number of multipliers needs to be minimized.

Increasing the number of multiplexers is permitted.

Further, assume that the timing constraints are

relaxed.

$[4$ Marks$]$

c$.$ Consider the circuit shown alongside. It consists of

instances of three identical inverters. The input

capacitance of the pin A for each inverter is $10$ ff $.$

The NLDM table for the timing arc A rarr ZN for the

inverter is also shown below the circuit.

The minimum and maximum transition time at the

input port IN are $10$ ps and $20$ ps $,$ respectively.

Ignore net capacitances. Compute

i$.$ Delay of the arc A rarr ZN for the instance

I$1$ for the setup analysis

ii$.$ Delay of the arc A rarr ZN for the instance

I$1$ for the hold analysis

$[2+2=4$ Marks $]$