public static void main(String[] args) {

char A = 65535, B = 0;

System.out.println((int)++A);

System.out.println((int)--B);

}

Unsigned Integer Representation Consider the following Java program to answer questions 14 15. Java implements char data type as unsigned integer with size 2 bytes. Note that, 2¹⁶ = 65536

1. What will be printed in the first line? Why?

a. 65536, because A will be pre-incremented before printing

b. 65535, because 65535 is the largest possible number in 2-byte unsigned representation. A cannot be incremented.

c. 0, because 65535 is the largest possible number in 2-byte unsigned representation. ++A will overflow to the smallest possible number

d. Nothing will be printed.

2. What will be printed in the second line? Why?

a. -1, because B will be pre-decremented before printing

b. 0, because 0 is the smallest possible number in 2-byte unsigned representation. B cannot be decremented

c. 65535, because 0 is the smallest possible number in 2-byte unsigned representation. --B will overflow to the largest possible number.

d. Nothing will be printed.

3. What is FFFF-FFFE in 2-byte unsigned integer representation?

a. 1

b. 10

c. 111

d. 110

Integer Representation Signed Magnitude & Twos Compliment

4. What is the disadvantage of signed-magnitude representation (compared to 2s compliment representation)?

a. Two zeros

b. Requires separate hardware units for Adding & Subtracting

c. May need to compare the magnitudes of the numbers before adding or subtracting

d. All of the above

public static void main(String[] args) {

int x = 32767; y = -32768;

System.out.println(++x);

System.out.println(--y);

}

Consider the following Java program to answer questions 18 19. Java implements Short data type as 2s complement integer with size 2 bytes. Note that, 2¹⁵ = 32767

5. What will be printed in the first line? Why?

a. 32768, because x will be pre-incremented before printing

b. 32767, because 32767 is the largest possible number in 2-byte 2s compliment representation. x cannot be incremented.

c. 0, because 32767 is the largest possible positive number in 2-byte 2s compliment representation. ++x will overflow to the smallest possible positive number

d. -32768, because 32767 is the largest possible positive number in 2-byte 2s compliment representation. ++x will overflow to the smallest possible number