public static void main(String] args) t String[] arguments = {"Long", "Not so short", "Last"); int list1= {1, 12, 222, 14, 987, 592); int list2 - (6, 5, 9, 7, 4, 13; int score = 10; Part A. if (countLongest(args)--0) score+-5; if (countlongest Carguments)--1) score+-5; Part B. if (countLongest (list1)--3) score+-5; if (countLongest(list2)--6) score+-5; System.out.println(score); 1/ 10 points just to compile Part A. Write a method countLongest that accepts an array of Strings as a parameter and returns the count (int) of elements in that array with length equal to the longest String in that array. See two examples above. Part B. Write a method countLongest that accepts an array of int's as a parameter and returns the count (int) of elements in that array with length (number of digits) equal to the largest int in that array. See two examples above. Yes, both methods have the same name countLongest but they differ in the parameters passed, so the compiler easily knows which method to call when and how. This is commonly known as a method overload