Put the following lines into a glowscript script and run them:

energies $=[8,7,1,6]$

$E=0$

for energy $in$ energies:

$,E=E+$ energy

$pr{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(E)$

Match the line of programming syntax with the lettered statement describing the action of the syntax.

A Adds the value of energy to the running total.

B Displays the sum of the energies $($i$.$e$.$ the total energy$).$

C Assigns an initial value to the running total.

D Loops through the energies and assigns each item to energy succesively.

$($c$)E=E+$ energy

c$.E=0.$

Q$.$ for energy in energies:

$(pr{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(E)$

Submit Answer Tries $0/99$

$($b$.)$ What is the value of the variable "energy" the second time through the for loop?

Tries $\frac{0}{99}$

$($c$.)$ What is the final value of $E?$