Question: ***Python 3.6*** Take the is_anagram() function and define a function called find_anagrams() that takes a string and returns a list of anagrams for that string

***Python 3.6***

Take the is_anagram() function and define a function called find_anagrams() that takes a string and returns a list of anagrams for that string from the wordlist.txt file.

The followings are my code. How can I use while loop instead of for loop?

def is_anagram(str1,str2): """returns True if the strings are anagrams of each other

str1,str2 -> bool""" str1 = str1.lower() str2 = str2.lower() d = {} for x in "abcdefghijklmnopqrstuvwxyz": if str1.count(x) != str2.count(x): return False return True

fp = open('wordlist.txt') for i, line in enumerate(fp.readlines()): if i == 0: countcase = int(i) board.append([]) else: if len(line[:-1]) == 0: currentBoard += 1 board.append([]) else: board[currentBoard].append(line[:-1]) fp.close()

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