Question: python 3.7 my code is not meet all requirements, please help me def integrate(f, n): if isinstance(n, int) and n > 0: def f_int(a, b):
python 3.7 my code is not meet all requirements, please help medef integrate(f, n): if isinstance(n, int) and n > 0: def f_int(a, b): if a > b: raise AssertionError('a should not be greater than b') else: dx = (b - a) / n integral = 0 while a
2. (5 pts) Define the integrate function, which takes two arguments: (1) a function call it f- (it is univariate: called with one numeric argument and returning a numeric result) and (2) an int value-call it n; if n is not an integer strictly greater than 0, raise an AssertionError exception (with an appropriate error message). The integrate function returns another function that takes two float arguments -call them a and b; if a is not less than or equal to b, raise an AssertionError exception (with an appropriate error message). When the returned function is called, it returns an approximation to the definite integral Sof(x)dx. We approximate this integral by adding up the area of a sequence of n rectangles, whose widths are all (b-a) (call this number dx, illustrated below) and whose heights are n values of f starting at f(a) and ending at f(a+ (n-1) dx). If we define int_f = integrate (f,5), Here is how to compute int_f(a,b). f(a+4dx) f(a+3dx) f(a) f(a+dx) f(a+2dx) For the fifth/last point, determine how integrate's function object can store an attribute named zcc (zero- crossing count) that computes the number of times f's value crosses 0: from negative (
Step by Step Solution
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock

def integrate(f, n): if isinstance(n, int) and n > 0: def f_int(a, b): if a > b: raise AssertionError('a should not be greater than b') else: dx = (b - a) / n integral = 0 while a