python

a) accumulator with straightforward iteration Using a for loop, implement a function named trig_sum that takes a single integer N and returns the value of the finite sum N cos ( 256 N=0 Hint: Define a variable with a value of zero, and then add each term in the sum to it as you loop over the indices. (Tip: Use the += operator when incrementing a variable by some amount.) [68]: def trig_sum(N, n=6): [69]: # Test code: Execute this immediately after executing your solution cell above it. assert allclose(trig_sum(), 1) assert allclose(trig_sum(10), 10.97103377436375) assert allclose(trig_sum(256), )